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x^2+16.5x=200
We move all terms to the left:
x^2+16.5x-(200)=0
a = 1; b = 16.5; c = -200;
Δ = b2-4ac
Δ = 16.52-4·1·(-200)
Δ = 1072.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16.5)-\sqrt{1072.25}}{2*1}=\frac{-16.5-\sqrt{1072.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16.5)+\sqrt{1072.25}}{2*1}=\frac{-16.5+\sqrt{1072.25}}{2} $
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